Answers>Maths>IB>Article

Find the differential of y=arcsinx

To differentiate we must use implicit differentiation. So: siny=x .Differentiating both sides we get (dy/dx)cosy=1, so (dy/dx)=1/cosy . Using the common identity (sin2(y)+cos2(y)=1) we can rewrite the denominator so we have: (dy/dx)=1/((1-sin2y)(1/2)) we can then substitute sin y with the identity we have in the first line of working: (dy/dx)=1/(1-x2)(1/2)

SG
Answered by Shivum G. Maths tutor

1092 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

Let f(x) = px^2 + qx - 4p, where p is different than 0. Showing your working, find the number of roots for f(x) = 0.


Solve the equation 8^(x-1) = 6^(3x) . Express your answer in terms of ln 2 and ln3 .


Sketch the graph of x^2 - y^2 = 16


Differentiation from first principles


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences