A jug containing 0.250 kg of liquid is put into a refrigerator. Its temperature decreased from 20°C to 15°C. The amount of energy transferred from the liquid was 5,250 J. Calculate the specific heat capacity of the liquid.
specific heat capacity = change in energy ÷ (mass × change in temperature) [1]= 5,250 ÷ (0.250 × 5) [1]= 4,200 J/kg°C [1]
BP
Related Physics GCSE answers
All answers ▸A coil is connected to a voltmeter. A bar magnet, initially held above the coil, is left to fall into the coil. Explain why the voltmeter shows a reading. How will the reading of the voltmeter be affected if the magnet is dropped from a greater height?
Does kinetic friction always oppose the direction of motion?
How much force is needed to bring a car to a halt over 5 seconds - the car is moving with velocity km/hr and with a mass of 1000kg.
What is the difference between alpha and gamma radiation?