Why does the discriminant b^2-4ac determine the number of roots of the quadratic equation ax^2+bx+c=0?

The rule for the discriminant: if b^2-4ac>0 then the quadratic has two roots if b^2-4ac=0 then the quadratic has one root if b^2-4ac<0 then the quadratic has no rootsRecall that the formula for solving the quadratic equation ax^2+bx+c=0 is x=(-b+(b^2-4ac)^0.5)/2a. Notice that the square-root of the discriminant is contained in this formula. If the discriminant is positive then it has a positive and negative square-root, giving two possible roots of the equation. If the discriminant is zero then this square-root term disappears giving only one root to the equation. Lastly, if the discriminant is negative then this square-root does not exist so the formula gives no answer.

DG

Related Further Mathematics GCSE answers

All answers ▸

In the expansion of (x-7)(3x**2+kx-3) the coefficient of x**2 is 0. i) Find the value of k ii) Find the coefficient of x. iii) write the fully expanded equation in terms of x


Make y the subject of the formula x = SQRT((y+1)/(y-2))


How do I determine if a stationary point on a curve is the maximum or minimum?


To differentiate a simple equation: y= 4x^3 + 7x