What is the equation of a circle with centre (3,4) and radius 4?

The general equation of a circle is (x-a)^2 + (y-b)^2 = r^2 where the centre is (a,b) and radius r.
Therefore the equation of this circle is (x-3)^2 +(y-4)^2 = 4^2 ...or 16
Sometimes its easiest to leave in r^2 form as expanding it can make work harder.

IL
Answered by Isobel L. Further Mathematics tutor

5594 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Solve the following simultanious equations: zy=28 and 2z-3y=13


f(x) = 3x^3 – x^2 – 20x – 12 (a) Use the factor theorem to show that (3x + 2) is a factor of f(x). [2 marks] (b) Factorise f(x) fully. [3 marks]


Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.


f(x) = 2x^3+6x^2-18x+1. For which values of x is f(x) an increasing function?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning