Calculate the enthalpy of combustion of 1 mol of ethanol using mean bond enthalpy (kJ/mol) data: C-C (347), C-H (413), C-O (358), O-H (464), O=O (498), C=O (805)
First we need to construct the equation of the combustion: C2H5OH(l) + 3O2(g) --> 2CO2(g) + 3H2O(l)Use aid of structural formulaLeft hand side (endothermic - requires energy):5(413) + 347 + 358 + 464 + 3(498) = 4728 kJ Right hand side (exothermic - releases energy):-[6(464) + 4(805)] = -6004 kJEnthalpy of combustion = 4728 - 6004 = -1276 kJ/mol
LL
Related Chemistry KS3 answers
All answers ▸What is the difference in structure between graphite and graphene?
Why can gases be compressed but liquids and solids can't?
Give the full ionic equation and net ionic reaction for Ba(NO3)2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2NaNO3 (aq)
Walk me through the separation of an insoluble solid from a liquid