A car travelling at 28 m/s brakes until it stops completely after travelling a distance of 15 m. Calculate the deceleration of the car.
· Firstly, we need to note down what we have: distance travelled, s =15 m; initial velocity, u = 28 ms-1; final velocity, v = 0 because the car comes to rest; we are looking for the deceleration hence a; since we are using s, u, v and a, we need to use the "suvat" equation that contains those four letters ----- v2 = u2 + 2as· By rearranging the equation ---- a = (v2 - u2) / 2s = -282 / (2 x 15) = -784/30 = -26 ms-2 (the minus sign is because deceleration is a decrease in speed rather than an increase)
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