A car travelling at 28 m/s brakes until it stops completely after travelling a distance of 15 m. Calculate the deceleration of the car.

·        Firstly, we need to note down what we have: distance travelled, s =15 m; initial velocity, u = 28 ms-1; final velocity, v = 0 because the car comes to rest; we are looking for the deceleration hence a; since we are using s, u, v and a, we need to use the "suvat" equation that contains those four letters ----- v2 = u2 + 2as·        By rearranging the equation ---- a = (v2 - u2) / 2s = -282 / (2 x 15) = -784/30 = -26 ms-2 (the minus sign is because deceleration is a decrease in speed rather than an increase)

OS
Answered by Oluyomi S. Physics tutor

3703 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A ball of mass m is thrown from the ground at the speed u=10ms^-1 at an angle of 30 degrees. Find the max height, the total flight time and the max distance it travels?Assume g=10ms^-1 and there is no air friction


Explain in terms of the motion of the molecules of the gas why the volume of gas must increase if the pressure is to remain constant as the gas is heated.


What is the difference between a scalar and a vector?


Two balls of mass 3kg and 7 kg respectively move towards one another with speeds 5ms^-1 and 2ms^-1 respectively on a smooth table. If they collide and join, what velocity do they move off with?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning