Can you explain rationalising surds?

Rationalising surds is the process of removing a square root from the bottom of a fraction. The way we do it is by using a little trick involving the difference of two squares.The difference of two squares is a way that we can factorise an expression of the form a2 - b2 as (a+b)(a-b).
So if we have an irrational number as the denominator of our fraction, we can apply this in reverse to remove the square root. It's easier to see it in action:
Say I have an irrational number such as 1/(1-(sqrt2)) - (sqrt2 is the square root of 2)
Then I can observe that the denominator is of the form a-b, where a = 1, b = sqrt 2.
Knowing this, I can use the difference of two squares in reverse by multiplying our irrational number by (a+b)/(a+b) (as this equals 1 so we aren't changing the value of the original irrational number).
The denominator then becomes a2 - b2 or -1 in this case, and our numerator becomes a+b, or 1 + sqrt 2.Our original number is now equal to -1 - sqrt 2. We have removed the denominator entirely, and in doing so made it much easier to work with.
1 / (1 - sqrt 2) = -1 - sqrt 2.
(It's much easier to explain with diagrams!)

HA

Related Further Mathematics GCSE answers

All answers ▸

Find the tangent to the equation y=x^2 -2x +4 when x=2


The line y = 3x-4 intersects the curve y = x^2 - a, where a is an unknown constant number. Find all possible values of a.


Find any stationary points in the function f(x) = 3x^2 + 2x


y=(6x^9 +x^8)/(2x^4), work out the value of d^2y/dx^2 when x=0.5