Find the coordinates of the minimum point of the function y=(x-5)(2x-2)
At the minimum point the gradient is zero so dy/dx=0. To find dy/dx, first expand out the brackets so y=2x^2 - 12x + 10. Using differentiation dy/dx=4x - 12. At the minimum 4x-12=0 so 4x=12 therefore x=3. Put this back into the original equation to find the y value of the minimum point y=(3-5)(2x3-2)=-8
PC
Answered by Phoebe C. • Further Mathematics tutor
2830 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Find dy/dx when y=2x^(4)+3x^(-1)
How do I determine if a stationary point on a curve is the maximum or minimum?
Express (7+ √5)/(3+√5) in the form a + b √5, where a and b are integers.
Work out the gradient of the curve y=x^3(x-3) at the point (3,17)