In decimal, what is the most negative number that can be represented using a 12-bit two’s complement binary integer?

In an n-bit two's complement representation scheme, the amount of numbers we can represent is 2n - 1. In 12- bit, it's 1111 1111 1111, or 4095 in decimal. The largest positive number must not have a leading 1, as it would have to be negative, so the largest positive number we can represent is 2n-1 - 1, which is 0111 1111 1111 or 2047 in decimal. Subtracting these two numbers 2047 - 4095 gives us, all the negative numbers we can represent, and since the smallest negative number is -1, this also equals to the largest negative number. -2048.

MD
Answered by Marek D. Computing tutor

15865 Views

See similar Computing A Level tutors

Related Computing A Level answers

All answers ▸

Express the number 208 as a) an 8-bit binary number b) an octal string c) a hexadecimal string


Write a Pseudocode function that returns the factorial of an integer input.


What is the decimal equivalent of the following sequence of bits, which represents an unsigned binary integer: 1101001. What is the decimal equivalent if the sequence in bits encodes a two’s complement binary integer.


What is the time complexity of Bubble Sort?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences