Show that (π‘₯ βˆ’ 1) is a factor of 𝑓(π‘₯)=2π‘₯^3 + π‘₯^2 βˆ’ 8π‘₯+ 5. Hence fully factorise 𝑓(π‘₯) fully.

For the show that part of the question simply substitute all the π‘₯'s in 𝑓(π‘₯) with 1, as the factor π‘₯ βˆ’ 1 means that π‘₯ - 1 = 0 therefore π‘₯ = 1. Once substituted in solve the equation and show that it is equal to 0 which proves π‘₯ βˆ’ 1 is a factor of the equation.For the second part use synthetic division to factorise the equation, diving 1 into the equation (with a remainder 0) to produce a quadratic equation which then can be solved through standard factoring. The solution is 𝑓(π‘₯) = (π‘₯ βˆ’ 1)(π‘₯ + 2)(π‘₯ βˆ’ 1)

CB

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