Show that the matrix A is non-singular for all real values of a

Given: A = [a -5; 2 a+4]. 1) First find the determinant of A using the known formula => det A = a2+ 4a + 10. A singular matrix is one in which it's determinant equals zero (the determinant of a matrix is a number that captures information about the characteristics of the matrix). The roots of the quadratic are complex, so the graph never equals zero/ no real roots. Therefore it must be a non-singular matrix.

Answered by Further Mathematics tutor

7055 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

What IS a Taylor Series?


Differentiate artanh(x) with respect to x


3 points lie in a plane; P1=i+2j+3k, P2=-3i+5j+2k, P3=i+2j+k. Find the Cartesian equation of the plane


Prove that 1+4+9+...+n^2 = n(n+1)(2n+1)/6.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences