A bowling ball is thrown into the alley, having velocity of 3 ms^-1 at the start of the bowling alley. It decelerates at a constant rate, before hitting the skittles at 2 ms^-1 after 4 s A) calculate the acceleration of the ball.

A)  acceleration (m/s2) = change in velocity (m/s) / time (s) 
A) -1.0 ms-1 / 4 s = -0.25 ms-2
B) Calculate the displacement the ball travelled before hitting the skittles and hence calculate the average velocity of the ball
d = 1/2 ( Vf + Vi ) × t = 0.5 x (3 + 2) ms -1 x 4 s = 10 m
Average velocity = distance / time = 10 m / 4 s = 2.5 m s-1
C) Finally, as the bowling ball weighs 10 kg, calculate the momentum with which it hits the skittles.
 momentum (kgm/s) = mass (kg) x velocity (m/s) = 10 kg x 2 ms-1 = 20 kg ms-1

AN
Answered by Alexander N. Physics tutor

2548 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Why do airbags make a car safer


A reflex occurs the iris of the human eye in response to changes in light levels - describe how these changes occur, referring to the changes in light level in your answer.


Why does a wire get hot when current flows through it?


A kettle requires 2400 Coulombs of charge to pass through its heating element, with a resistance of 6 Ohms, in a time of 200 seconds in order to boil the water inside it. Calculate the current flowing and the power of the kettle.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning