A bowling ball is thrown into the alley, having velocity of 3 ms^-1 at the start of the bowling alley. It decelerates at a constant rate, before hitting the skittles at 2 ms^-1 after 4 s A) calculate the acceleration of the ball.

A)  acceleration (m/s2) = change in velocity (m/s) / time (s) 
A) -1.0 ms-1 / 4 s = -0.25 ms-2
B) Calculate the displacement the ball travelled before hitting the skittles and hence calculate the average velocity of the ball
d = 1/2 ( Vf + Vi ) × t = 0.5 x (3 + 2) ms -1 x 4 s = 10 m
Average velocity = distance / time = 10 m / 4 s = 2.5 m s-1
C) Finally, as the bowling ball weighs 10 kg, calculate the momentum with which it hits the skittles.
 momentum (kgm/s) = mass (kg) x velocity (m/s) = 10 kg x 2 ms-1 = 20 kg ms-1

AN

Related Physics GCSE answers

All answers ▸

Why do rays of light change direction as they pass from air to a glass block?


What is a chain reaction?


A car driver has to make an emergency stop. The braking distance depends on the speed of the car. For the same braking force, what happens to the braking distance if the speed doubles?


What is Fleming's left hand rule?