A bowling ball is thrown into the alley, having velocity of 3 ms^-1 at the start of the bowling alley. It decelerates at a constant rate, before hitting the skittles at 2 ms^-1 after 4 s A) calculate the acceleration of the ball.

A)  acceleration (m/s2) = change in velocity (m/s) / time (s) 
A) -1.0 ms-1 / 4 s = -0.25 ms-2
B) Calculate the displacement the ball travelled before hitting the skittles and hence calculate the average velocity of the ball
d = 1/2 ( Vf + Vi ) × t = 0.5 x (3 + 2) ms -1 x 4 s = 10 m
Average velocity = distance / time = 10 m / 4 s = 2.5 m s-1
C) Finally, as the bowling ball weighs 10 kg, calculate the momentum with which it hits the skittles.
 momentum (kgm/s) = mass (kg) x velocity (m/s) = 10 kg x 2 ms-1 = 20 kg ms-1

Answered by Alexander N. Physics tutor

1266 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Why protons held together in the nucleus?


Calculate the acceleration if a force of 500N is exerted on a mass of 20kg


If Newton's third law is correct, why are walls not indestructible? In applying a force to a wall, if it breaks surely it is not giving an equal and opposite force.


If a cricket ball of mass 500g is thrown upwards from the ground with an initial velocity of 20 m/s, how high will the ball reach?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy