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First we must remember our equations of motion, (SUVAT equations).S = Displacement U = Initial velocity V = Final velocity A = Acceleration T = TimeV = U + A*TS = U*T + (1/2)*A*T^{2} V^{2 }= U^{2} + 2*A*SS = (1/2)*(U+V)*TThen we must identify what information the question has given us.The intial velocity (U) is 6ms*(0.3)S = 0.45m

The maximum height the ball reaches is 0.45m

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