Find the coordinates that correspond to the maximum point of the following equation: y = −16x^2 + 160x - 256

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To solve this problem, the maximum and minimum points of equations can be deduced through the differentiation process. This looks at the gradient of the function and the maximum/minimum value occurs when the gradient is zero.

The differentiation process is as follows:


df(x)/dx = nAx(n-1)

The equation

y = −16x2 + 160x - 256


dy/dx= -32x+160

after differentiation and set dy/dx=0



and the corresponding value for y is:

y=-16(52)+160(5)-256= 144

And so the coordinate of the maximum point is:


Michael W. GCSE Maths tutor, IB Maths tutor, A Level Maths tutor, GCS...

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