Find the coordinates that correspond to the maximum point of the following equation: y = −16x^2 + 160x - 256

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To solve this problem, the maximum and minimum points of equations can be deduced through the differentiation process. This looks at the gradient of the function and the maximum/minimum value occurs when the gradient is zero.

The differentiation process is as follows:

f(x)=Axn

df(x)/dx = nAx(n-1)

The equation

y = −16x2 + 160x - 256

becomes

dy/dx= -32x+160

after differentiation and set dy/dx=0

0=-32x+160

x=5

and the corresponding value for y is:

y=-16(52)+160(5)-256= 144

And so the coordinate of the maximum point is:

(5,144)

Michael W. GCSE Maths tutor, IB Maths tutor, A Level Maths tutor, GCS...

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