Answers>Maths>IB>Article

Find the coordinates that correspond to the maximum point of the following equation: y = −16x^2 + 160x - 256

To solve this problem, the maximum and minimum points of equations can be deduced through the differentiation process. This looks at the gradient of the function and the maximum/minimum value occurs when the gradient is zero.

The differentiation process is as follows:

f(x)=Axn

df(x)/dx = nAx(n-1)

The equation

y = −16x2 + 160x - 256

becomes

dy/dx= -32x+160

after differentiation and set dy/dx=0

0=-32x+160

x=5

and the corresponding value for y is:

y=-16(52)+160(5)-256= 144

And so the coordinate of the maximum point is:

(5,144)

MW
Answered by Michael W. Maths tutor

2989 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

Determine the integral: ∫5x^4dx


The function f has a local extreme at point (1,4). If f''(x)=3x^2+2x, then find f(0)?


How to find the derivative of sqrt(x) from first principles?


Solve the equation 8^(x-1) = 6^(3x) . Express your answer in terms of ln 2 and ln3 .


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences