Calculate pH of 0.1M NaOH

pH=14-pOHpOH=-log([OH(-)])NaOH-> Na(+)+OH(-)[NaOH]=[OH(-)]=0.1MpOH=-log(0.1)=1pH=14-1=13

LK
Answered by Laura K. Chemistry tutor

27285 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Explain the bonding in and the shape of a benzene molecule.


What is the difference between pH and pKa?


What is the rate of a reaction and how can you determine it experimentally?


Describe briefly how you would show that manganese(II) ions catalyse the reaction between manganate(VII) ions and ethanedioate ions, in dilute sulphuric acid.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning