If the equation of a curve is x^2 + 9x + 8 = y, then differentiate it.

First we must establish how to differentiate terms individually. This is done by using the simple method of multiplying the X by the power, and subtracting one away from the power. To make it easier we will differentiate each term individually and then put the equation back together at the end. 1. x^2 2x^(2-1) =2x 2. 9x 19x^(1-1) = 9x^0 =91 = 9 3. 8 08^(0-1) = 0 Therefore dy/dx = 2x+9 This would be useful if the gradient needed to be found. To find the gradient at a point all you need to do is substitute in the X value.

TT

Related Further Mathematics GCSE answers

All answers ▸

Why does the discriminant b^2-4ac determine the number of roots of the quadratic equation ax^2+bx+c=0?


Factorise the following quadratic x^2 - 8 + 16


Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.


Express (7+ √5)/(3+√5) in the form a + b √5, where a and b are integers.