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If a car sets off from rest with a constant acceleration of 3 m/(s^2), what would its speed be after 5 seconds?

Firstly we write down all known variables: Initial speed (u)=0 m/s, Acceleration (a)=3 m/s², Time (t)=5s. Final velocity (v)=?Therefore, the equation chosen to solve the problem would be: v=u+a...

Answered by Shahnaan M. • Physics tutor

1700 Views

Find the values of x given the equation (4x^2)-3x+1=2 using the quadratic formula.

4x²-3x+1=2The first step is to rearrange the equation, equating it to zero: 4x²-3x+1-2=0 which gives 4x²-3x-1=0. Next we apply the quadratic formula: x=(-...

Answered by Shahnaan M. • Maths tutor

3178 Views

25cm3 NaOH was titrated with 0.05mol dm-3 HCl. 21.5m3 of HCl neutralised 25cm3 of NaOH. What is the concentration of NaOH in mol dm-3?

NaOH + HCl --> NaCl + H₂O 1 : 1 : 1 moles (mol) = concentration (mol dm^-3) x volume (dm³)

Answered by Britta A. • Chemistry tutor

4880 Views

Describe the adaptations for efficient gas exchange in the lungs?
For efficient diffusion there must be a concentration gradient that is maintained, a large surface area to volume ration and a short distance for the gases to diffuse across. There are adaptations at the ...
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Answered by Isla M. • Biology tutor
6920 Views

Time, T, is measured in tenths of a second with respect to distance x, is given by T(x)= 5(36+(x^2))^(1/2)+4(20-x). Find the value of x which minimises the time taken, hence calculate the minimum time.
To solve this problem we first must look into the given formula for time (T). It is stated, in the question, that the time taken is dependent on distance x. From this we can infer that the following probl...
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Answered by Aziz H. • Maths tutor
3259 Views

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If a car sets off from rest with a constant acceleration of 3 m/(s^2), what would its speed be after 5 seconds?

Find the values of x given the equation (4x^2)-3x+1=2 using the quadratic formula.

25cm3 NaOH was titrated with 0.05mol dm-3 HCl. 21.5m3 of HCl neutralised 25cm3 of NaOH. What is the concentration of NaOH in mol dm-3?

Describe the adaptations for efficient gas exchange in the lungs?

Time, T, is measured in tenths of a second with respect to distance x, is given by T(x)= 5(36+(x^2))^(1/2)+4(20-x). Find the value of x which minimises the time taken, hence calculate the minimum time.

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