Top answers

All subjects
All levels

Two functions, y1 & y2, are given by y1=x^2+16x+4; y2=2(3x+2). Find analytically the volume of the solid created by revolving the area between the two curves by 2pi radians around the x-axis. N.B. y2>y1 on the interval between the points of intersection.

Setting the two equations equal to one another to find the intersection boundaries:x^2+16x+4=6x+4; x^2+16x+4-6x-4=0; x^2+10x=0;x(x+10)=0; x=0, x=-10. Setting up the vol...

FG
Answered by Filippos G. Maths tutor
2233 Views

How does Shakespeare present Lear's daughters in Act One, Scene One?

From its outset, Shakespeare’s ‘King Lear’ challenges the fundamental qualities of human relationships and connections that are traditionally thought to be stable. In particular, it is the institution of ...

MG
Answered by Millicent G. English tutor
5520 Views

Find exact solution to 2ln(2x+1) - 10 =0

Isolate the 'ln term'
2ln(2x+1) = 10ln(2x+1) = 5
Take to the exponential power form
e^(ln(2x+1)) = e^52x+1 = e^5
Simplify
2x = e^5 -1x = (e^5-1)/2

JD
Answered by Johnny D. Maths tutor
3868 Views

In the photoelectric effect, what happens as you increase the frequency of light keeping the same intensity constant?

E=hf, so as you increase the frequency of light, the energy of each photon hitting the metal surface is greater. Thus the electrons liberated from the surface of the metal have a greater maximum kinetic e...

AJ
Answered by Alexander J. Physics tutor
23928 Views

A roll of card has an area of 43 m^2. A postcard has an area of 125 cm^2. How many post cards can be cut from the roll, assuming there is no wastage? (calculator question)

This question is assessing your knowledge of units and their conversion. Notice that the area units of the roll of card and the postcard are different, so it is important that before we carry out any calc...

HG
Answered by Hafsah G. Maths tutor
2968 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning