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 x^3=1=e^2(pi)ik 

x=e^2(pi)ik/3

The three roots are

k=0    x=1 

k=1    x=e^2(pi)*i/3

k=-1   x=e^-2(pi)ik/3

Paper 1 is an unseen commentary paper. It can seem tricky at first but once you get the hang of it you can do very well on this paper!  I think its helpful to have a formula of how to answer these questio...

x^2= 4(x^2 - 6x + 9)

x^2= 4x^2- 24x + 36

3x^2 - 24x + 36= 0

(x-2)(x-6)=0

x= 2 or x=6

Approaching an analysis of a large work such as a symphony can seem daunting at first, but the task can be made easy and enjoyable by setting out what features of the music to look for (such as harmony/ m...

Firstly, note that a stationary point can either be a local maximum, local minimum or point of inflexion. Now suppose you have a differentiable function (a graph which has a unique gradient/derivative at ...