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In a titration, 50 cm3 of sodium hydroxide with a concentration of 0.3 mol/dm3 was neutralised by 60 cm3 of hydrochloric acid. Calculate the concentration of the hydrochloric acid in mol/dm3.

HCl + NaOH = NaCl + H2O. Moles = volume (dm3) x concentration (mol/dm3). Moles of NaOH: volume x concentration = (50/1000) x 0.3 = 0.015 moles. 1 to 1 ratio of HCl to NaOH, so there were 0.015 moles of HC...

AV
Answered by Aarushi V. Chemistry tutor
24626 Views

Simplify 3x^(2)+13x-30/x^(2)-32

First of all spot that the bottom of the fraction is a result of the difference of two squares and can be rearranged to (x+6)(x-6), making the fraction equal to 3x^(2)+13x-30/(x+6)(x-6). Use this knowledg...

NP
Answered by Nicolaas P. Maths tutor
3885 Views

find dy/dx of the equation y=ln(x)2x^2

Here it is necessary to use the chain rule to solve the derivative. If we equate our equation in terms of the following notation: ln(x)='u'and 2x^2='v' and use the chain rule formula dy/dx=udv/dx+vdu/dx w...

PG
Answered by Pierce G. Maths tutor
3589 Views

Solve (4-2x)/(x+1)=x

To solve this equation, we need to collect all of the x^2 terms and the x terms together. To do this we should start by getting rid of the fraction on the left-hand side by multiplying both sides by the d...

EK
Answered by Emily K. Maths tutor
8799 Views

How do I keep a good line of argument throughout my essay?

Hello, thank you for the question. Concerning maintaining a good strong argument throughout your essay, it's always good to keep using the question throughout. For example, starting your paragraphs (main ...

ER
4833 Views

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