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Starting with the initial integral of int(exp(x).cos(x))dx we can see that this is going to have to be integrated by parts. This states that the integral of (u . dv/dx)dx is equal to u.v - int(v . du/d...
To find the gradient of any curve, we take the derivative. So in this case, we need to take dy/dx. We do this by multiplying the term by the power on x, and then lowering the power by one. For example, fo...
Key points include:
Criminal behaviour...
1) is learnt. Southerland is behaviourist in this respect.
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Learning vocab is not easy and different methods work for different people. Here are just a few suggestions of ways to try...
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Let u = x and dv/dx = sin(x),
By using the general expression of:
integral(u multiply dv/dx)dx = [u multiply v] - integral(v multiply du/dx)dx, and by realising that:
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