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A simple way to prove this is to sub in the values that we are given. so f(x) will represent our equation x^3-3x+1 (that is f(x) = x^3-3x+1)f(-2) = -1 < 0f(-1) = 3 > 0The first thing we notice is th...
Start off with:x2+x=12Subtract 12 from both sides:x2+x-12=0Factorise:(x-3)(x+4)=0Solution is therefore:x=3 or x=-4
As you go across the period, the nuclear charge (or number of protons increase) but the shielding (or the number of shells) stays the same as all of the elements are on the same period. This causes the nu...
Here we can use integration by parts. Notice that ln(x) can be written as ln(x)1, so we can integrate 1 and differentiate ln(x).Then using the formula int(uv') dx = uv - int(u'v) dx, we...
Here we have to differentiate a constant raised to the power of a variable. To make it easier, let u=sinx and so our function can now be treated as y=a^u. Remembering that A = e^(LnA), a^u = e^(Ln(a^u)). ...
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