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This is an example where we use integration by parts, but it is not immediately obvious where to start.Recall the integration by parts formula ∫u(dv/dx) dx = uv - ∫(du/dx)v dxKEY STEP:OCAnswered by Oliver C. • Further Mathematics tutor12633 Views
The technique we need to use to solve this integral is called integration by parts. The parts formula is: the integral of (uv' dx) = uv - the integral of (u'v dx) (where u and v are functions of x). We ne...
I have linked the solution to this problem here.https://www.icloud.com/iclouddrive/0mLKDeFREhbvTJm6D09jFakcw#Solution
x = (-2 +/- sqrt(4-8))/2 therefore x = - 1 +/- i, where i is the imaginary unit
x = i is a solution, and all the coefficients are real, so x = -i must also be a solution:2x^3+3x^2+2x+3 = 0(x+i)(x-i)(Ax+B) = 0 (we argued above that this must be the case)(x^2+1)(Ax+B) = 0(x^2+1)(2x+3) ...
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