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We use the quotient rule here which states that if y = f(x)/g(x) then dy/dx = (f'(x)g(x) - g'(x)f(x)) / (g(x)^2). Here f(x) = 4x and g(x) = x^2 + 5, so we have f'(x) = 4 , g'(x) = 2x. This gives us dy/dx ...

We know that an equation has equal roots if the sqrt(b^2-4ac) term in the quadratic equation is equal to zero. Therefore using this information we can form an expression for k to be (-k)^2-4(2k-3)(k-1)=0....

As V=(h⁶+16)^1/2 -4, the chain rule can be used to calculate dV/dh.

dV/dh=3h⁵(h⁶+16)^-1/2

h=2 can be su...

Roots = where line touches x-axis. Set equation equal to 0 as y=0 at the x-axis. Now we need to solve for the x values at which y=0. Quadratic is now 0=x^2+5x+6. Factorise quadratic: 0=(x+3)(x+2). Now you...

f'(x)= 3x^2+1/3x^(-2/3)

To differentiate you need to multiply the coefficant of the x dependent terms by the powers and then the power of x goes down by one. 

For example: differentiate f(x)...