Top answers

Maths
A Level

How do I find the equation of the tangent to y = e^(x^2) at the point x = 4?

This question can be broken up into two main parts, one you're probably familiar with from C1 + C2 and one which is newer. The first part relates to differentiating a compound function (where a function i...

SH
Answered by Sam H. • Maths tutor
9347 Views

differentiate with respect to 'x' : ln(x^2 + 3x + 5)

(2x + 3) / (x2 + 3x + 5)

AS
Answered by Alec S. • Maths tutor
4980 Views

Differentiate with respect to x: y=(6x^2-1)/2sqrt(x)

1st Step: Must separate the fractions and simplify:

y= (6x2-1)/2sqrt(x)= 6x2/(2x1/2) - 1/(2x1/2) 

Cancel 6 with 2 and x

ES
Answered by Elena S. • Maths tutor
8906 Views

i) It is given that f(x)=(-5-33x)/((1+x)(1+5x)), express f(x) in the form A/(1+x) + B/(1+5x) where A,B are integers. ii) hence express the integral of f(x) between x=3 and x=0 in the form (p/q)ln4 where p,q are integers.

i) -7/(1+x) + 2/(1+5x) ii) (-31/5)ln4

DT
Answered by Damon T. • Maths tutor
4139 Views

find the integral of ((3x-2)/(6x^2-8x+3)) with respect to x between x=2 and x=1. (hint use substitution u=denominator)

(ln11)/4

DT
Answered by Damon T. • Maths tutor
4217 Views

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