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We will call the integral I, so I = integral of 1/(3+(x+4)1/2) dx between 0 and 5. First substitute u=3+(x+4)1/2 into the equation to get I = integral of 1/u dx between 0 and 5 Next ...
a) 2ln(2x + 1)-4=0
-> ln(2x + 1)-2=0
-> ln(2x + 1)=2
-> (2x + 1)=e2
-> 2x = e2 -1
-> x = (e2 -1)/2
b) 7xELAnswered by Elizabeth L. • Maths tutor4430 Views
This question can be broken up into two main parts, one you're probably familiar with from C1 + C2 and one which is newer. The first part relates to differentiating a compound function (where a function i...
(2x + 3) / (x2 + 3x + 5)
1st Step: Must separate the fractions and simplify:
y= (6x2-1)/2sqrt(x)= 6x2/(2x1/2) - 1/(2x1/2)
Cancel 6 with 2 and xESAnswered by Elena S. • Maths tutor8342 Views
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