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One helpful method for solving questions like these is to sketch the curve in stages. First begin with the straight line y=3x+4 (taking 3x+4 from within the modulus lines) crossing the x axis at -4/3 and ...

sin(A+B) ≡ sin(A)cos(B) + sin(B)cos(A)

⇒ sin(75°) = sin(30+45)° = sin(30°)cos(45°) + sin(45°)cos(30°)

= ½ × 1/√2 + 1/√2 ×(√3)/2 = 1/(2√2) + (√3)/(2√2)

= (1+√3)/(2√2)

e^x, the differential of the exponential function is itself.

Simply take B from A i = 10-3=7 j= -3-2=-5 k= 2-5=-3 SO the velocity is (7i-5j-3k)

dy/dx= 6x + 30x^4 - 2/x^2