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Let u = x and dv/dx = sin(x),
By using the general expression of:
integral(u multiply dv/dx)dx = [u multiply v] - integral(v multiply du/dx)dx, and by realising that:
All we do here is break down into three parts: x2, 6x & 1.x2 becomes 2x as we multiply by the power and then decrease the power by one.6x becomes 6 and 1 becomes 0.So alltogether...
first notice the integral is in the form f'(x)/f(x), and indefinite integrals of this form are ln|f(x)|+c. therefore the integral is [ln|x4+x|] between limits 1 and 2. subbing in li...
Differentiating the above equation with respet to y:dx/dy = m;Substituting the value of m in the given form:x = (dx/dy) y i.e. the solution is(dx/dy) y - x = 0
Find the positive value of x such that logx64 = 2Using the logarithm rules, we know that we can rearrange the given equation into the form:x2 = 64Knowing this, we s...
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