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Differentiate the function; f(x)=1/((5-2x^3)^2)

We know from the properties of basic indices that a -x =1/a x , so 1/((5-2x 3 ) 2 =(5-2x 3 ) -2 where in this case, a=5-2x 3 and x=2. Then the function is differentiable by the chain rule. As dy/dx=dy/duXdu/...
BK
Answered by Benjamin K. • Maths tutor
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Differentiate (2^x)(5x^2+5x)^2.

This is a relatively difficult equation to differentiate as there are various parts to consider.Firstly, we will let u=2^x and v=(5x^2+5x)^2 in the product rule. Then the differential of u is (2^x)ln(2). We ...
GH
Answered by George H. • Maths tutor
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Determine the tangent to the curve y = sin^2(x)/x at the point, x = pi/2. Leave your answer in the form ax+by+c=0

First determine the y coordinate of the curve at the given x coordinate, in this case, y = sin 2 (pi/2)/(pi/2) = 1 2 /(pi/2) = 2/piDifferentiate the function with respect to x to determine the gradient of th...
TB
Answered by Thomas B. • Maths tutor
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How many books and modules and what are they all about?

For A-Level Maths you have 6 books (3 AS level and 3 A2 level) C1 (Core Maths 1) the easiest book and simple algebra and polynomials (non-calculator paper) 1h30min long C2 (Core Maths 2) continuation of C1 a...
SN
Answered by Siddharth N. • Maths tutor
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f(x) = 2 / (x^2 + 2). Find g, the inverse of f.

Rewrite as y = 2 / (x^2 + 2). Swap all x and y symbols to create x = 2 / (y^2 + 2). Rearrange for y to reach y=g(x)=sqrt( (2-2x) / x ).
AR
Answered by Alfie R. • Maths tutor
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