Differentiate (2^x)(5x^2+5x)^2.

This is a relatively difficult equation to differentiate as there are various parts to consider.Firstly, we will let u=2^x and v=(5x^2+5x)^2 in the product rule. Then the differential of u is (2^x)ln(2). We must remember how to differentiate exponential here where the exponent is a variable.Then the differential of v is 2(10x+5)(5x^2+5x) by using the chain rule. If we substitute the correct values into the product rule equation we get an answer of
2(2^x)(10x+5)(5x^2+5x)+(2^x)ln(2)(5x^2+5x)^2.
No need to simplify this.

GH

Related Maths A Level answers

All answers ▸

Find the binomial expansion of ((x^2) − 5)^3


Sketch y = 9x – 4x^3, showing where the curve crosses the x axis.


Using the product rule, differentiate: y = (x^2 - 1)(x^3 + 3).


Find the general solution, in degrees, of the equation 2sin(3x+45°)=1. Use your general solution to find the solution of 2sin(3x+45°)=1 that is closest to 200 °.