Differentiate (2^x)(5x^2+5x)^2.

This is a relatively difficult equation to differentiate as there are various parts to consider.Firstly, we will let u=2^x and v=(5x^2+5x)^2 in the product rule. Then the differential of u is (2^x)ln(2). We must remember how to differentiate exponential here where the exponent is a variable.Then the differential of v is 2(10x+5)(5x^2+5x) by using the chain rule. If we substitute the correct values into the product rule equation we get an answer of
2(2^x)(10x+5)(5x^2+5x)+(2^x)ln(2)(5x^2+5x)^2.
No need to simplify this.

GH
Answered by George H. Maths tutor

3655 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find dy/dx such that y=(e^x)(3x+1)^2.


Given that y = ((4x+3)^5)(sin2x), find dy/dx


Using the substitution u = 2 + √(2x + 1), or other suitable substitutions, find the exact value of 4 0 1 ∫ 2 (2 1) +√ +x dx giving your answer in the form A + 2ln B, where A is an integer and B is a positive constant


How to factorise 6x^2-11x-10?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning