Differentiate (2^x)(5x^2+5x)^2.

This is a relatively difficult equation to differentiate as there are various parts to consider.Firstly, we will let u=2^x and v=(5x^2+5x)^2 in the product rule. Then the differential of u is (2^x)ln(2). We must remember how to differentiate exponential here where the exponent is a variable.Then the differential of v is 2(10x+5)(5x^2+5x) by using the chain rule. If we substitute the correct values into the product rule equation we get an answer of
2(2^x)(10x+5)(5x^2+5x)+(2^x)ln(2)(5x^2+5x)^2.
No need to simplify this.

GH
Answered by George H. Maths tutor

3162 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

"Solve cos(3x +20) = 0.6 for 0 < x < 360" - why are there more than one solution, and how do I find all of them?


f ( x ) = 2 x ^3 − 5 x ^2 + ax + a. Given that (x + 2) is a factor of f ( x ), find the value of the constant a. (3 marker)


Integrate (tanx)^2


Given that 9 sin^2y-2 sin y cos y=8 show that (tany - 4)(tany + 2)= 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences