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Find the coordinates of the stationary points for the curve y = x^4 - 2*x^2 + 5.

First solve to find dy/dx.dy/dx = 4 x^3 - 4 xThe stationary points occur when dy/dx = 0. Solve the equation to find the values of x for when dy/dx = 0.4x(x^2 - 1) = 0 x = 0, x = 1, x = -1Finally sub in the v...
MW
Answered by Matthew W. • Maths tutor
6174 Views

The curve C has equation y = x^3 - 3x^2 - 9x + 14. Find the co-ordinates and nature of each of the stationery points of C.

Step 1: Differentiate y with respect to x. dy/dx = 3x^2 - 6x - 9 Step 2: Equate to zero and solve. 3x^2 - 6x - 9 = 0(x - 3)(x+1) = 0x = 3, x = -1 Step 3: Substitute into original equation to find y. At x = 3...
DA
Answered by Daniel A. • Maths tutor
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Differentiate 8x^3+4x^2+2

24x^2+8x
MB
Answered by Maximilian B. • Maths tutor
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y = 2t^2, and x = 3t^3 - 2. Find dy/dx in terms of t.

dy/dt = 4t dx/dt = 9t^2dy/dx = dy/dt * dt/dx= 4/(9t)
TM
Answered by Theo M. • Maths tutor
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If I throw a ball, of mass 2kg, straight up in the air, with velocity 10ms-1, how long until it lands? Assume gravity = 10ms-2

Using SUVAT-s = ut + 1/2 at^2Subbing in... 0 = 2t - 5t^2t = 5/2 = 2.5
TM
Answered by Theo M. • Maths tutor
3533 Views