y = 2t^2, and x = 3t^3 - 2. Find dy/dx in terms of t.

dy/dt = 4t dx/dt = 9t^2dy/dx = dy/dt * dt/dx= 4/(9t)

TM
Answered by Theo M. Maths tutor

6092 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve has equation x^2 + 2xy – 3y^2 + 16 = 0. Find the coordinates of the points on the curve where dy/dx =0


Find the equation of the tangent to the curve y^3 - 4x^2 - 3xy + 25 = 0 at the point (2,-3).


Use logarithms to solve the equation 3^(2x+1) = 4^100


What is the centre and radius of the circle with the equation x(x-2)+y(y+6)+4=0 ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning