Find the coordinates of the stationary points for the curve y = x^4 - 2*x^2 + 5.

First solve to find dy/dx.dy/dx = 4x^3 - 4xThe stationary points occur when dy/dx = 0. Solve the equation to find the values of x for when dy/dx = 0.4x(x^2 - 1) = 0 x = 0, x = 1, x = -1Finally sub in the values of x into the equation for y to find the corresponding y values.y = 5, y = 8, y = 8

MW

Related Maths A Level answers

All answers ▸

If y=5x+4x^3, find dy/dx.


Which Real values of x satisfy 3/ln(x) = ln(x) + 2?


integrate( x^3+4x^2+3)dx


Differentiate with respect to x: F(x)=(x^2+1)^2