Top answers

(i) Find the coordinates of the stationary point on the curve y = 3x^2 − 6/x − 2. [5] (ii) Determine whether the stationary point is a maximum point or a minimum point.

i) dy/dx = 0dy/dx = 6x + 6/x^2 6x + 6/x^2 = 06x^3 + 6 = 0x^3 + 1 = 0x^3 = -1x = -1y = 7(-1, 7)ii) d^2y/dx^2 = 6 - 12/x^3 x = -1 6-12/(-1)^3 = 18>0 therefore, minimum point
DY
Answered by Dila Y. • Maths tutor
9232 Views

Find the Binomial Expansion of (1-5x)^4.

First I would set up how i was taught using Pascals Triange. As this is to the power of 4 the numbers across will be 1 4 6 4 1.Then I would multiply each number by the correct power of either (-5x) or (1). A...
MV
7101 Views

Integrate the function (3x+4)^2 using methods of expansion and substitution

For expansion:(3x+4) 2 =9x 2 +24x+16, go through expansion in online classroom. Now we integrate this using standard polynomial integration rules. For substitution: use the substitution u=3x+4, and use the i...
MR
Answered by Morgan R. • Maths tutor
4506 Views

Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.

y = x 3 - 2xdy/dx = 3x 2 -2plugging in x = 2, therefore gradient = 10using the formula to get the equation of a line y -y 1 =m(x - x 1 )substitute y 1 =4 and x 1 =2 to get the answer-10x + y + 16 = 0
KS
Answered by Kevalee S. • Maths tutor
6480 Views

I always mix up my integration and differentiation. How do i stop this?

First thing to do is practice. Practice makes perfect. You are not going to get through your differentiation and integration by doing only a couple of questions on these topics. You need to take one topic at...
YP
Answered by Yasmin P. • Maths tutor
5460 Views