Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.

y = x3- 2xdy/dx = 3x2 -2plugging in x = 2, therefore gradient = 10using the formula to get the equation of a line y -y1=m(x - x1)substitute y1=4 and x1=2 to get the answer-10x + y + 16 = 0

KS
Answered by Kevalee S. Maths tutor

5494 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

If f'(x)=3x(x - 1), find f(x)


Given y = ln((2x+3)/(7x^3 +1)). Find dy/dx


Find the values of k for which the equation (2k-3)x^2 - kx + (k-1) = 0


Using the product rule, differentiate y=(2x)(e^3x)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences