(i) Find the coordinates of the stationary point on the curve y = 3x^2 − 6/x − 2. [5] (ii) Determine whether the stationary point is a maximum point or a minimum point.
i) dy/dx = 0dy/dx = 6x + 6/x^2 6x + 6/x^2 = 06x^3 + 6 = 0x^3 + 1 = 0x^3 = -1x = -1y = 7(-1, 7)ii) d^2y/dx^2 = 6 - 12/x^3 x = -1 6-12/(-1)^3 = 18>0 therefore, minimum point
DY
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