Top answers

Differentiating (x^2)(sinx) Using the Product Rule

Firstly, what is the product rule? What does it actually say? Well, it tells us how to differentiate a function of the form uv - the product of the functions u and v. If y = uv, the product rule says: dy/dx ...
EM
Answered by Edward M. • Maths tutor
6032 Views

Use the chain rule to differentiate y=(x-3)^(-3)

Hint: the chain rule states that for y=u(x) ^a, the derivative will be dy/dx = dy/du * du/dxSo we just need to find dy/du and du/dx!In this case u(x)=x-3, so du/dx = 1.from y=u^(-3), dy/du = -3u^(-4).This me...
RT
Answered by Rosemary T. • Maths tutor
5830 Views

Solve the inequality x < 4 - |2x + 1|.

In order to deal with the modulus sign, we must take account of 2 possible cases: Case 1: |2x + 1| = (2x +1). In this case we can solve algebraicly, preserving the inequality sign, to get that x &lt; 4 -(2x ...
JC
Answered by Joe C. • Maths tutor
8627 Views

Find the exact value of the gradient of the curve y = e^(2- x)ln(3x- 2). at the point on the curve where x = 2.

To solve this problem, we must first differentiate: Identify that we are able to use the product rule as our expression is of the form y = f(x)g(x) where f(x) = e^(2- x) and g(x) = ln(3x- 2). Hence f'(x) = -...
JC
Answered by Joe C. • Maths tutor
10693 Views

how do integrate an equation with a surd or a fraction?

most people are immediately confused when they see a surd or a fraction because they find it hard to apply the rule of integration directly to them. however it is not as complicated as it looks. all that nee...
AD
Answered by Abdullah D. • Maths tutor
10843 Views