Use the chain rule to differentiate y=(x-3)^(-3)

Hint: the chain rule states that for y=u(x) ^a, the derivative will be dy/dx = dy/du * du/dxSo we just need to find dy/du and du/dx!In this case u(x)=x-3, so du/dx = 1.from y=u^(-3), dy/du = -3u^(-4).This means we know dy/dx = -3u^(-4) * 1Converting from u to x, we get dy/dx = -3 (x-3)^(-4) .... done! 

RT
Answered by Rosemary T. Maths tutor

4839 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

f(x) = x^3+2x^2-x-2 . Solve for f(x) = 0


Tom drink drives two days a week, the chance of him being caught per day is 1 in 100. What is the chance he will not be driving after a) one week? b) one year?


Integrate the function f(x)=lnx


Differentiate the function f(x) = sin(x)/(x^2 +1) , giving your answer in the form of a single fraction. Is x=0 a stationary point of this curve?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences