Use the chain rule to differentiate y=(x-3)^(-3)
Hint: the chain rule states that for y=u(x) ^a, the derivative will be dy/dx = dy/du * du/dxSo we just need to find dy/du and du/dx!In this case u(x)=x-3, so du/dx = 1.from y=u^(-3), dy/du = -3u^(-4).This means we know dy/dx = -3u^(-4) * 1Converting from u to x, we get dy/dx = -3 (x-3)^(-4) .... done!
RT
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