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Maths
A Level

A curve has the equation: x^2(4+y) - 2y^2 = 0 Find an expression for dy/dx in terms of x and y.

First of all expand the brackets in the equation. Then you can differentiate each term with respect to x. As one of the terms will be a product of x and y the product rule must be used to find the differe...

CM
Answered by Carlotta M. Maths tutor
3786 Views

Prove that, if 1 + 3x^2 + x^3 < (1+x)^3, then x>0

(1+x)^3 = x^3 + 3x^2 + 3x + 1 (Can be calculated straight away by binomial method or by multiplying brackets individually)
if (1+x)^3 > 1 + 3x^2 + x^3then: x^3 + 3x^2 + 3x + 1 > 1 + 3x^2 +...

VT
Answered by Vigneswaran T. Maths tutor
14867 Views

Differentiate y = xe^(2x).

We want to find dy/dx. We find this using the product rule by setting the functions f(x) = x and g(x) = e2x. With these functions, we can write the equation as y = f(x)g(x), so by applying the ...

ML
Answered by Matthew L. Maths tutor
26955 Views

what is the integral of ln(x)

answer may not be obvious at first, but by using intergration by parts, treating part 1 as lnx and part 2 as 1, you will get xlnx-1

AF
Answered by Anthony F. Maths tutor
2761 Views

A curve has the equation 6x^(3/2) + 5y^2 = 2 (a) By differentiating implicitly, find dy/dx in terms of x and y. (b) Hence, find the gradient of the curve at the point (4, 3).

(a) To differentiate implicitly, differentiate x’s as normal and differentiate y’s with respect to y before multiplying by dy/dx. Therefore the differentiating the curve gives
9x^(1/2) + 10y*(dy/dx) ...

ML
Answered by Matthew L. Maths tutor
3331 Views

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