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Differentiate the equation.Let the derivative equal to 0 and get x.Substitute the value of x into the original equation to get y.

a) 54-45+3a+18=0 3a+27=0 3a=-27 and thus a=-9b) 2x^3 – 5x^2 -9x + 18 = (x-3) (2x^2 +bx-6)to find b ; collect the x^2 terms so bx^2-6x^2=-5x^2 and thus b=1c) when comparing f(y) and f(x) we see ...

e^{x^2} --------> dy/dx = 2xe^{x^2}

use the formula integral(uv') = uv - integral(vu') so the tricky integral can be avoided (this formula can be derived from integrating the product rule) so in these questions all you need to ...