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Differentiate the equation.Let the derivative equal to 0 and get x.Substitute the value of x into the original equation to get y.
a) 54-45+3a+18=0 3a+27=0 3a=-27 and thus a=-9b) 2x^3 – 5x^2 -9x + 18 = (x-3) (2x^2 +bx-6)to find b ; collect the x^2 terms so bx^2-6x^2=-5x^2 and thus b=1c) when comparing f(y) and f(x) we see ...
ex^2 --------> dy/dx = 2xex^2
use the formula integral(uv') = uv - integral(vu') so the tricky integral can be avoided (this formula can be derived from integrating the product rule) so in these questions all you need to ...
First expand the equation, giving us 2x^3 + 5x^2Then you can differentiate the equation by multiplying the number at the front of x by its power.Only then, we need to subtract 1 from the power.This gives ...
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