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cos^2(A) + sin^2(A) = 1, sin(A+B) = sinAcosB + cosAsinB, cos(A+B) = cosAcosB - sinAsinB, sin2A = 2sinAcosA (if A = B), cos2A = cos^2(A) - sin^2(A) (if A = B), cos2A = 1 - 2sin^2(A) => sin^2(A) = 1/2(1 ...
This equation can be solved using separation of variables. Firstly we rearrange the equation so that all of the y's are on the left hand side and all of the x's are on the right: 1/y2* dy = 6x ...
(4-8x)^(-3/2) =Factoring out 4^(-3/2) to make binomial expansion easier(1-2x)^(-3/2) =Using the binomial series expansion in the formula booklet, up to the term in x^3<...
3/2x2 -2/5x5/2 +C
sin(x)2 + cos(x)2 = 1 divide by cos(x)2 tan(x)2 + 1 = sec(x)2 therefore tan(x)2 = sec(x)2 - 1 integral of sec(x)2 - 1 rwt x = tan(x) - x + C therefore the integral of tan(x)2 rwt x = tan(x) - x + C
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