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Start by using the formula d = sqrt((x₂-x₁)²+(y₂-y₁)²)Therefore, substituting in our coordinates from P and Q:Length PQ = sqrt((-8-4)^...

2cot2x= 2(1/tan2x)= 2(1/(2tanx/1-tan²x))=2(1-tan²x)/2tanx= (1-tan²x)/tanx(1-tan²x)/tanx +tanx=(1-tan²x)/tanx +tan²x/tanx=1/tanx=cotx

f^-1(x)=(e^x-1)/3 g(x)=3/(3x+1)

The product rule is used to differentiate this since we are trying to differentiate the product of 2 parts--x and ln(x)So using the product rule which is d/dx=u.(dv/dx) +v.(du/dx)let u=x and v=ln(x)then d...

Start with finding limits by setting 3x - x^2 = 0, then factorise x(3 - x) = 0. Therefore x = 0 or 3. The area is the integral of 3x - x^2 between x = 0 and 3, sub in 3 and 0 into 3(x^2)/2 - (x^3)/3, whic...