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Maths
A Level

A Curve has parametric equation x=2sin(t), y= 1+cos(2t), -pi/2<=t<=pi/2. a) Find dy/dx when t=pi/3. b) Find the Cartesian equation for the curve in form y=f(x), -k<=x<=k. c) Find the range of f(x)

x=2sin(t), y=1+cos(2t)

a) By chain rule, dy/dx = (dy/dt)/(dx/dt)
dy/dt = -2sin(2t), dx/dt= 2cos(t)
dy/dx= -sin(2t)/cos(t)
dy/dx=-2sin(t)cos(t)/cos(t)
dy/dx=-2sin(t)

MB
Answered by Max B. Maths tutor
10417 Views

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dy/dx = -3 +12x^-4 d^2y/dx^2 = -48x^-5

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The curve C has the parametric equations x=4t+3 and y+ 4t +8 +5/(2t). Find the value of dy/dx at the point on curve C where t=2.

a) What can we find from what we have been given?

dx/dt and dy/dt

How can we relate these values to dy/dx?

In the context of equations that only contain two variables, their derivativ...

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Intergrating with respect to time, you get that v = u + at. Knowing that velocity is just the rate of change of your position ds/dt = v, and sustituting the previous expression for v, you get ds/dt = u + ...

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Answered by Ben W. Maths tutor
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