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x=2sin(t), y=1+cos(2t) a) By chain rule, dy/dx = (dy/dt)/(dx/dt) dy/dt = -2sin(2t), dx/dt= 2cos(t) dy/dx= -sin(2t)/cos(t) dy/dx=-2sin(t)cos(t)/cos(t) dy/dx=-2sin(t)MBAnswered by Max B. • Maths tutor10417 Views
dy/dx = -3 +12x^-4 d^2y/dx^2 = -48x^-5
cos(theta)-(4/3)cos3(theta)
a) What can we find from what we have been given?
dx/dt and dy/dt
How can we relate these values to dy/dx?
In the context of equations that only contain two variables, their derivativ...
Intergrating with respect to time, you get that v = u + at. Knowing that velocity is just the rate of change of your position ds/dt = v, and sustituting the previous expression for v, you get ds/dt = u + ...
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