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Maths
A Level

How do I integrate by parts?

When we integrate by parts, we begin by setting the first term to equal some variable U, the second term in the integral we set to be dv/dx. Then we differentiate the U to obtain du/dx and integrate dv/dx...

LM
Answered by Louis M. Maths tutor
4059 Views

Solve for -pi < x < pi: tanx = 4cotx + 3

tanx = 4cotx + 3  - Multiply through by tan to form a quadratic. tan^2x = 4 + 3tanx - Simplify by allowing y to equal tanx. y^2 = 4 + 3y - Rearange to standard quadratic form. y^2 - 3y -4 = 0 - Factorise....

ZL
Answered by Zak L. Maths tutor
6152 Views

How would you differentiate 3x^4 - 2x^2 + 9x - 1

First we follow the "times by the power and take one from the power" rule. This is the easiest way to remember how to differentiate anything. 

So (3x4)x(4-1) -(2x2)x(2-1)<...

CE
Answered by Cathy E. Maths tutor
3261 Views

Integrate the following expression with respect to x by parts: (2*x)*sin(x)

The integration by parts formula: S:udv/dx = uv -  S:v*du/dx, where S: means "Integral of with respect to x" 

Let 2*x be u and sin(x) be dv/dx

So du/dx =2 and v= -cos(x)

DP
Answered by David P. Maths tutor
3210 Views

When I integrate by parts how do I know which part of the equation is u and v'?

To determine which function is your u value in the by parts equation, you can use the acronym LATE to find the order of precedence for this value. LATE stands for: Logarithmic functions Arithmetric functi...

BA
Answered by Ben A. Maths tutor
3292 Views

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