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Differentiate by multiply by the power and then minus 1 from the power. Use the rule: y= ax^b -> dy/dx = abx^(b-1)

dy/dx = 3 x 2x^(3-1) + -1 x 2x^(-1-1) + 0 dy/dx = 6x^2 - 2x^-2

Use the method of integration by parts. uv-integral(v.du/dx). Make u equal to ln(x) and dv/dx equal to 1. Therefore v=x and du/dx=1/x. Hence uv=xln(x). And v.du/dx=x/x=1. Substituting these into the 'by p...

To solve this question we will use the chain rule, as we can see that we have one function being applied to another, i.e sin is being applied to cos(x).

This means we are able to replace the origin...

Use the rule of "bringing down the power" and then reducing the power by 1. Start with 4x^2. "Bring down" the 2 to make (4)(2)x^2, then reduce the power by 1 to make 8x. Now repeat thi...

a) x^(2) + 6x + 1 = 0 (x + 3)^(2) - 8 = 0 x = - 3 + sqrt(8) or x = - 3 - sqrt(8)

b) (x-5)(x+1) = 0 x = -1 or 5

c) using answer to part b: (x-5)(x+1) < 0 draw its graph then: -1<x<5<...