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When thinking about stationary points, it is important to remember that these points happen when the gradient of the curve is 0 (-> dy/dx = 0), or if you prefer, when the rate of change of a graph is 0...

y = x²(cos(x)) therefore we will need to use the product rule, 

dy/dx = u dv/dx + v du/dx

where u = x² and v = cos(x)

du/dx = 2x and dv/d...

Differentiation can be done term-by-term, so we can treat the 5x³, -2x² and 2 separately. We can also 'take out' the coefficients: to differentiate 5x³, for example, di...

The problem with this fraction is the "i" on the denominator, it is not rational. To rationalise this fraction we use the complex conjugate.

This sounds more co...

We can use Pythagoras' Theorem applied to co-ordinates of these points.