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How do you find the x co-ordinates of the stationary points of a curve with the equation y = 10x - 2x^2 - 2x^3

First to find the stationary points, you have to differentiate the equation of the curve y, to give you (dy/dx) = 10 - 4x - 6x^2After differentiating the equations, the points at which the curve is stationar...
DM
Answered by David M. • Maths tutor
3690 Views

Integrate 2x^5 + 7x^3 - (3/x^2)

Integrating x n gives you x n+1 /(n+1).Integral of 2x 5 is 2x 6 /6 = x 6 /3. The integral of 7x 3 is 7x 4 /4.-(3/x 2 ) can be rewritten as -3x -2 . Therefore the integral is -3x -1 /-1 = 3x -1 = 3/x. As it i...
AP
Answered by Alexander P. • Maths tutor
4732 Views

Differentiate y = 5x^3 + 7x + 3 with respect to x

When differentiating with respect to x, we multiply the coefficient of the 'x' by the power of the 'x', and subtract one from the power of 'x'. For example:y = 5x^5dy/dx = (5 5)x^(5-1) = 25x^4If the power of...
JK
Answered by Jordan K. • Maths tutor
4520 Views

(Core 2) Show that the region bounded by the curve y = 7x+ 6 - (1/x^2), the x axis and the lines x = 1 and x = 2 equals 16

The question wants us to confirm the answer so the marks will be in the method unlike most questions which require you to find the answer. How to approach this is by thinking what ways can we calculate areas...
LJ
Answered by Lewis J. • Maths tutor
4471 Views

A curve (C) with equation y=3x^(0.5)-x^(1.5) cuts the X axis at point A and the origin, calculate the co-ordinates of point A.

Insert 0 into the equation in place of Y as the Y co-ordinate is always 0 across the X-Axis.0 = 3x^0.5-x^1.5The x^0.5 can be factored out from the 3x^0.5 and the x^1.5 giving you...x^0.5(3-x^1) = 0 [As x^0.5...
JM
Answered by Jack M. • Maths tutor
3798 Views