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integrate( x^3+4x^2+3)dx

=(x^4)/4+(4x^3)/3 + 3x + c
RH
Answered by Rory H. Maths tutor
4352 Views

The curve C has a equation y=(2x-3)^5; point P (0.5,-32)lies on that curve. Work out the equation to the tangent to C at point P in the form of y=mx+c

Firstly you should work out the first derivative of the equation y= After differentiating the equation, sub the x value of the point P into the first derivative. This should give you the gradient of the equa...
MR
Answered by Mohammed R. Maths tutor
3828 Views

Given y = 2sin(θ) and x = 3cos(θ) find dy/dx.

The function is defined parametrically so we usually approach these questions using chain rule.Recall that: dy/dθ * dθ/dx = dy/dx So we will need to differentiate each expression individually then multiply t...
JC
Answered by Jacob C. Maths tutor
5641 Views

How can I find the normal to a curve at a given point?

Take the curve y = 2x 2 - 4 and point P (2,4) . a) First, find the straight line tangent to the curve at point P . This will have the gradient of the curve at point P . To find it, differentiate: dy/dx = 4x ...
AP
Answered by Artyom P. Maths tutor
5123 Views

Sketch y = 9x – 4x^3, showing where the curve crosses the x axis.

First you should look at the equation and try and get a sense of the general shape of the graph. The highest power in here is a 3, so this is a cubic graph. The coefficient (number in front of the x^3) is a ...
AE
Answered by Anais E. Maths tutor
5983 Views