Integrate 2x^5 + 7x^3 - (3/x^2)
Integrating xn gives you xn+1/(n+1).Integral of 2x5 is 2x6/6 = x6/3. The integral of 7x3 is 7x4/4.-(3/x2) can be rewritten as -3x-2. Therefore the integral is -3x-1/-1 = 3x-1 = 3/x. As it is an indefinite integral there is also a constant of integration c.Answer: (x6/3) + (7x4/4) + (3/x) + c
AP
Related Maths A Level answers
All answers ▸Use the substitution u = 2^x to find the exact value of ⌠(2^x)/(2^x +1)^2 dx between 1 and 0.
A curve is defined by the parametric equations x = 3 - 4t, and y = 1 + 2/t. Find dy/dx in terms of t.
Integrate | x^7 (ln x)^2 dx ( | used in place of sigma throughout question)
Please explain Pythgoras Theorem