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Integrate 2x^5 + 7x^3 - (3/x^2)

Integrating xⁿ gives you xⁿ⁺¹/(n+1).Integral of 2x⁵ is 2x⁶/6 = x⁶/3. The integral of 7x³ is 7x⁴/4.-(3/x²) can be rewritten as -3x^-2. Therefore the integral is -3x^-1/-1 = 3x^-1 = 3/x. As it is an indefinite integral there is also a constant of integration c.Answer: (x⁶/3) + (7x⁴/4) + (3/x) + c

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Integrate 2x^5 + 7x^3 - (3/x^2)

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