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What is the equation of the tangent at the point (2,1) of the curve with equation x^2 + 3x + 4.

dy/dx = 2x + 3, m = dy/dx = 7 Equation of tangent is a straight line hence we use y-y1 = m(x-x1), y-1 = 7(x - 2), y = 7x - 13
BA
Answered by Bishr A. • Maths tutor
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How do I find dy/dx for a given equation, once this is found how do I find the value of x such that dy/dx = 0.

From a given equation y = mx + c. Finding dy/dx allows us to see the gradient of the curve. In order to do this we can follow the formula: When y = x n , dy/dx = nx n-1 . Let us use this in a real scenario. ...
SA
Answered by Sebastian A. • Maths tutor
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Solve for x (where 0<x<360) 2sin^2(x) - sin(x) - 1 = 0

Factorise the equation (the equation is quadratic in sin(x) )2 sin 2 (x) - sin(x) - 1 = 0(2sin(x) + 1)(sin(x) - 1) = 0Work out the solutions to the quadratic equation2sin(x) +1 = 0 or sin(x) - 1 = 0sin(x) = ...
Answered by • Maths tutor
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What is the chain rule?

Up until now you may have been given functions like f(x)= 7x^3 +cos(x) and been told just to differentiate. What your teacher really meant was to differentiate with respect to x. The chain rule allows us to ...
JM
Answered by James M. • Maths tutor
3663 Views

Find the integral of 4sqrt(x) - 6/x^3.

The easiest way to do this is to break the integral up into it's separate parts. We have:integral of 4sqrt(x)andintegral of -6/x^3 Both of which have constants that can be taken out, i.e. 4 and 6, respective...
SP
Answered by Sam P. • Maths tutor
3272 Views